2x^2+26x=180

Solution for 2x^2+26x=180 equation:

2x^2+26x=180

We move all terms to the left:

2x^2+26x-(180)=0

a = 2; b = 26; c = -180;
Δ = b2-4ac
Δ = 262-4·2·(-180)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-46}{2*2}=\frac{-72}{4}
=-18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+46}{2*2}=\frac{20}{4}
=5
$